Thursday, November 13, 2008

Generating Representations

One way of generating representations is to take some representations one knows and combine them in some fashion.There are three standard methods of obtaining new representations from old, namely, direct sum of representations, tensor products of representations, and dual representations.


Direct Sum of Representations

Let G be a matrix Lie group and let Π1, Π2, ..., Πm be representations of G acting on vector spaces V1, V2, ..., Vm. Then, the direct sum of  Π1, Π2, ..., Πm is a representation Π1 Π2 ... Πm of G acting on the space V1 V2 ... Vm, defined by [Π1 Π2 ... Πm (A)] (v1, v2, ..., vm) = (Π1(A)v1, Π2(A)v2, ..., Πm(A)vm) for all A G. 


Similarly, if g is a Lie algebra, and π1, π2, ..., πm are representations of g acting on V1, V2, ..., Vm, then we define the direct sum of  π1, π2, ..., πm , acting on  V1 V2 ... Vm by [π1 π2 ... πm (X)] (v1, v2, ..., vm) = (π1(X)v1, π2(X)v2, ..., πm(X)vm) for all X g.


Tensor Products of Representations

Consider an element u of U and v of V, the "product" of these two are denoted by uv. The space UV is then the space of linear combination of such products. The space of elements is in the form of a1u1v1 + a2u2v2 + ... + anunvn . The product is not necessary commutative (vu is in different space) but is bilinear ((u1+ au2)v = u1 v + au2 v, u (v1+ av2) = u v1 + au v2). 


If U and V are finite-dimensional real or complex vector spaces, then tensor product (W, ϕ) of U and V is a vector space W, together with a bilinear map ϕ : U x V --> W with the following property: If ψ is any bilinear map of UxV into a vector space X, then there exists a unique linear map ψ of W into X. Bilinear maps on UxV turn into linear maps on W. Suppose e1, e2 , en is a basis for U and f1, f2 , fm  is a basis for V. Then {ϕ(ei, fj) | 1 ≤ i ≤ n, 1≤ j ≤ m} is a basis for W. In this case, {eifj | 1 ≤ i ≤ n, 1≤ j ≤ m} is a basis for UV and dim (UV) = (dim U)(dim V). 


The tensor product (W, ϕ)  is unique up to canonical isomorphism. That is, if (W1, ϕ1) and (W2, ϕ2) are two tensor products, then there exists a unique vector space isomorphism Φ : W1 --> W2 . 


The defining property of UV is called the universal property of tensor products. Suppose that ψ(u,v) is some bilinear expression in (u,v). Then , the universal property says precisely that there is a unique linear map T(= ψ ) such that T(uv) = ψ(u,v). Let A : U --> U and B : V --> V be linear operators. Then, there exists a unique linear operator from UV to UV, denoted by AB, such that (AB)(uv) = (Au)(Bv) for all u U and v V. Moreover, (A1B1)(A2B2) = (A1A2)⊗(B1B2). 


There are two approaches to define tensor of representations. 

(A) Starts with a representation of a group G acting on a space V and a representation of another group H acting on space U and produces a representation of the product group GxH acting on space UV.


(B) Starts with two different representations of the same group G, acting on spaces U and V, and produces a representation of G acting on UV.


(A) Let G and H be matrix Lie groups. Let Π1 be a representation of G acting on a space U and let Π2 be a representation of G acting on a space V. Then, the tensor product of Π1 and Π2 is a representation Π1Π2 of GxH acting on UV defined by  Π1Π2 (A,B) =  Π1(A)Π2(B) for all A G and B H. Let  π1 π2 denote the associated representation of the Lie algebra of GxH, namely gh. Then, for all X g and Y h, π1 π2(X,Y) = π1(X) I + I π2(Y).  


(B) Let G be a matrix Lie groups and let Π1 and Π2 be representation of G acting on a space V1 and V2. Then, the tensor product of Π1 and Π2 is a representation of G acting on V1 V2 defined by Π1Π2 (A) =  Π1(A)Π2(A) for all A G. The associated Lie algebra g satisfies π1 π2(X) = π1(X) I  + I π2(X) all X g. 


Suppose Π1 and Π2 are irreducible representations of a group G. If regard Π1Π2 as representation of G, it may no longer be irreducible. If it is not irreducible, one can attempt to decompose it as a direct sum of irreducible representations. This process is called the Clebsch-Gordan theory. In the physics, the problem of analyzing tensor products of representations of SU(2) is called "addition of angular momentum."


Dual Representations

A linear functional on a vector space V is a linear map of V into C. If v1, v2, ..., vn is a basis for V, then for each set of constants a1, a2, ..., an, there is a unique linear functional ϕ such that ϕ(vk) = ak. If V is a finite-dimensional complex vector space, then the dual space to V, denoted by V*, is the set of all linear functionals on V. This is also a vector space and its dimension is the same as that of V.  If A is a linear operator on V, let Atr denote the dual or transpose operator on V*, (Atrϕ)(v) = ϕ(Av) for all ϕ V*, v  V. Note that the matrix of Atr is the transpose of the matrix A and not the conjugate transpose. If A and B are linear operators on V, then (AB)tr = Btr Atr . 


Suppose G is a matrix Lie group and Π is a representation of G acting on a finite-dimensional vector space V. Then, the dual representation Π* to Π is the representation of G acting on V* given by Π*(g) = [Π(g-1)]tr . Similarly, if π is a representation of a Lie algebra g acting on a finite-dimensional vector space V, then π* is the representation of g acting on V* given by  π*(g) = -π(X)tr. The dual representation is also called contragredient representation. Note that the transpose is an order-reversing operation, we cannot simply define Π*(g) = Π(g)tr. This would not be a representation. 

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